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i have run into a problem... [message #213132]

Mon, 14 August 2006 02:47

jnz
Messages: 3396
Registered: July 2006
Location: 30th century

Karma: 0

General (3 Stars)

i have run into a problem that i cannot solve:

index.php?t=getfile&id=1517&private=0

if i ignore the error i can telnet port 3002 and send data over fine the fds will print it. so why do i get it?

#include "Socket.h"
#include <string>
#include <windows.h>
using namespace std;

DWORD WINAPI parse(LPVOID lpParam)
{

	SocketServer in(3002,5);
	while (1) 
	{
		Socket* s=in.Accept();
		while (1) 
		{
			std::string r = s->ReceiveLine();
			if (r.empty()) 
				break;
			Console_Output(r.c_str());
		}
	}
	return 0;
}

if i comment this function body out(exept "return 0;") it will not error.

here is the SocketServer code: http://www.adp-gmbh.ch/win/misc/sockets.html

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Re: i have run into a problem... [message #213133 is a reply to message #213132]

Mon, 14 August 2006 03:01

light
Messages: 988
Registered: January 2005

Karma: 0

Colonel

I'm more a Java person but i'll ask the stupid questions anyway.

1. Does break; break both while loops of just one? (And why do you have 2 whie loops anyway? Why not this:

Quote:

#include "Socket.h"
#include <string>
#include <windows.h>
using namespace std;

DWORD WINAPI parse(LPVOID lpParam)
{

SocketServer in(3002,5);
Socket* s=in.Accept();
std::string r = "";
while (true)
{
r = s->ReceiveLine();
if (r.empty()) {
break;
}
else {
Console_Output(r.c_str());
}
}
}

2. Would it not save resources and allocation to declare your strong outside your second while loop?

3. EDIT: Wait, on reflection using return 0; inside a method that is not main() is probably your issue. Try removing it. Return 0 basically means "All went well, terminate program, but only main() should call it.

http://www.azupload.com/displayImage.php/setid2745.png

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Re: i have run into a problem... [message #213138 is a reply to message #213133]

Mon, 14 August 2006 04:07

jnz
Messages: 3396
Registered: July 2006
Location: 30th century

Karma: 0

General (3 Stars)

light wrote on Mon, 14 August 2006 11:01

I'm more a Java person but i'll ask the stupid questions anyway.

1. Does break; break both while loops of just one? (And why do

it will just break the loop that it is in.

light wrote on Mon, 14 August 2006 11:01

2. Would it not save resources and allocation to declare your strong outside your second while loop?

Yes. do you mean "string" *not sarcasticly*

light wrote on Mon, 14 August 2006 11:01

3. EDIT: Wait, on reflection using return 0; inside a method that is not main() is probably your issue. Try removing it. Return 0 basically means "All went well, terminate program, but only main() should call it.

No, the decloration suggests that it should return a DWORD. return 0; does not mean "all went well", it means in "main" terminate program with exit code 0.

in any function, as far as i know, exept a thread return 0 means that the function when finished will be equal to 0. in breif terms. this may not be all correct, but it is when i think of it.

BTW: a "DWORD" is a number (i think) i don't see why you can't just use "int"

thanks for your reply.

[Updated on: Mon, 14 August 2006 04:08]

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Re: i have run into a problem... [message #213249 is a reply to message #213132]

Mon, 14 August 2006 16:43

light
Messages: 988
Registered: January 2005

Karma: 0

Colonel

In that case won't your code enter an infinite loop?

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Re: i have run into a problem... [message #213252 is a reply to message #213132]

Mon, 14 August 2006 16:46

danpaul88
Messages: 5795
Registered: June 2004
Location: England

Karma: 0

General (5 Stars)

Also, your code says while(l), but as far as I can see you have not initialised l... you probably need to do
int l = 1;
or something before starting the while loops (unless its defined in one of those include files)

EDIT: And yes, that code would produce an infinite loop.

http://steamsignature.com/card/1/76561197975867233.png

[Updated on: Mon, 14 August 2006 16:46]

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Re: i have run into a problem... [message #213344 is a reply to message #213132]

Tue, 15 August 2006 06:49

jnz
Messages: 3396
Registered: July 2006
Location: 30th century

Karma: 0

General (3 Stars)

the code doesn't say "while(l)" it says "while(1);" since it is a new thread it doesn't matter if it goes into a infinit loop because it wont halt the program. it goes into an infinite loop to recive data on port 3002.

after alot of debuggung, i have fixed it. it turns out that LoadScopes() function must be called 2 times because i put my function call just after that. when it got called the 2nd time it tryed to open port 3002 which is already open and it crashes.

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